Week 6 - Recitation (2nd for test 2)
- Which reaction below represents the electron affinity of Li?
- Li(g) + e- -> Li^-(g)
- Li(g) -> Li^+(g) + e-
- Li(g) + e- -> Li^+(g)
- Li^+(g) -> Li(g) + e-
- Li^+(g) + e- -> Li(g)
- Place the following in order of increasing metallic character
- Rb Cs K Na
- K < Cs < Na < Rb
- Na < K < Rb < Cs
- Cs < Rb < K < Na
- K < Cs < Rb < Na
- Na < Rb < Cs < K
- Why does an electron found in a 2s orbital have a lower energy than an electron found in a 2p orbital in multi-electron systems?
- Electrons in the 2s orbital are shielded by electrons in the 2p
- There are more nodes found in the 2s orbital
- Electrons in the 2s orbital can penetrate the 1s orbital and be closer to the nucleus
- The larger number of electrons found in the 2p orbital leads to greater repulsion
- The shape of the orbital ultimately determines the energy of the electrons
- Which ion has the largest radius?
- Na+
- Ga3+
- K+
- Mg2+
- Ca+
- Place the following in order of increasing atomic radius
- As O Br
- As < Br < O
- O < As < Br
- Br < As < O
- As < O < Br
- O < Br < As
- Place the following in order of decreasing radius
- Te2- F- O2-
- F- > O2- > Te2-
- F- > Te2- > O2-
- Te2- > O2- > F-
- Te2- > F- > O2-
- O2- > F- > Te2-
- Place the following in order of increasing IE
- N F As
- N < As < F
- As < N < F
- F < N < As
- As < F < N
- F < As < N
- Identify the number of valence electrons in Cl-
- 6
- 7
- 8
- 5
- 4
- Give the ground state electron configuration for Se2-
- [Ar] 4s2 3d10 4p4
- [Ar] 4s2 3d10 4p2
- [Ar] 4s2 4p6
- [Ar] 4s2 3d10 4p6
- [Ar] 4s2 3d8 4p6
- Give the name for SnO
- tin I oxide
- tin II oxide
- tin III oxide
- tin IV oxide
- Write the name for Sn(SO4)2
- tin (I) sulfite
- tin (IV) sulfite
- tin sulfide
- tin (II) sulfite
- tin (I) sulfate