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Practice Problem: Combustion Reaction How many grams of products are formed during the combustion of 100. g of ethanol? (and how much oxygen is consumed)?

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Alkali Metal Reaction: A Type of Chemical Reaction

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  • Overview of Alkali Metals:
  • The alkali metals (group 1A) have ns1 outer electron configurations.
    • Form +1 cation to “achieve” noble gas configuration.
  • The reactions of the alkali metals with nonmetals are vigorous.
  • Common reaction for alkali metals (M) is with halogens (X)
    • 2 M + X2 → 2 MX
    • Example: 2 Na(s) + Cl2(g) → 2 NaCl(s)
  • The alkali metals react vigorously with water to form the dissolved alkali metal ion, the hydroxide ion, and hydrogen gas:
    • 2 M(s) + 2 H2O(l) → 2 M+(aq) + 2 OH–(aq) + H2(g)
    • The reaction is highly exothermic and can be explosive because the heat from the reaction can ignite the hydrogen gas.

Halogen Reaction: A Type of Chemical Reaction

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  • Halogen Overview:
  • Group 7 elements that have ns2np5 outer electron configurations:
    • Mostly form –1 anions (F only forms –1 anion) to achieve the “noble gas configuration”
    • Most reactive of the nonmetal elements
  • The halogens (X) tend to react with metals especially with Group 1 and 2A metals to form ionic compounds such as metal halides (MXn).
    • 2 M + n X2 → 2 MXn
    • Example: 2 Fe(s) + 3 Cl2(g) → 2 FeCl3(s)
  • The halogens react with hydrogen to form hydrogen halides.
    • H2( g) + X2 → 2 HX(g)

Clicker 1

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  • Two samples of calcium and fluoride are decomposed into their constituent elements. The first sample showed that the yield of products was 100% (really!). If the second sample produced 294 mg of fluorine, how many g of calcium were formed? (Ca: 40.08, F: 19.00)
    • A) 0.280 g
    • B) 3.10 * 10^2 g
    • C) 3.13 g
    • D) 0.310 g
    • E) 2.80 * 10^2 g

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  • End of chapter 8

Chapter 9

  • Introduction to Solutions & Aqueous Reactions

Why a whole “introductory” chapter on chemistry in water?

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  • Water is ubiquitous: human body is 50-65% water
  • Water is (relatively) cheap
  • Water is a good solvent
  • Many reactions go faster in water

Solution Concentration and Solution Stoichiometry

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  • When table salt is mixed with water, it seems to disappear or become a liquid, and the mixture is homogeneous.
    • The salt is still there, as you can tell from the taste or simply boiling away the water.
  • Homogeneous mixtures are called solutions.
  • The component of the solution that changes state is called the solute.
  • The component that keeps its state is called the solvent.

Solution Concentration: Categories

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  • Dilute solutions have a small amount of solute compared to solvent.
  • Concentrated solutions have a large amount of solute compared to solvent
  • Can also describe Quantitatively

OLD Solution Concentration: Molality

  • A (not so) common way to express a solution concentration is molality (M).
    • Molality is the amount of solute (in moles) divided by the mass of solvent (in kg). CH102

Solution Concentration: Molarity

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Solution Concentration: Molarity

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  • A common way to express a solution concentration is molarity (M).
    • Molarity is the amount of solute (in moles) divided by the volume of solution (in liters).

Using Molarity in Calculations

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  • The molarity of a solution can be used as a conversion factor between moles of the solute and liters of the solution.
    • For example: A 0.500 M NaCl solution contains 0.500 mol NaCl for every liter of solution.

Practice Problem: Calculating Concentrations

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  • What is the molarity of a solution made by dissolving 25.5 g of KBr in enough water to give 1.75 L of solution?

Clicker 2

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  • Determine the molarity of a solution formed by dissolving 97.7 g LiBr in enough water to yield 750.0 mL of solution. (Li: 6.941, Br: 79.90)
    • A) 1.50 M
    • B) 1.18 M
    • C) 0.130 M
    • D) 0.768 M
    • E) 2.30 M

Practice Problem: Calculating Concentrations

  • Audio 0:34:48.656203 How many liters of a 0.125 M NaOH solution contain 0.255 mol of NaOH?

Solution Dilution: Making a Solution from a Solution: C1·V1 = C2·V2

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  • A dilution is when a new solution is prepared from a stock solution (more concentrated solution).
  • To make solutions of lower concentrations from these stock solutions, more solvent is added.
    • The amount of solute doesn’t change; just the volume of solution changes:
      • moles solute in solution 1 = moles solute in solution 2
      • The concentrations and volumes of the stock and new solutions are inversely proportional.
  • The mathematical relationship is C1·V1 = C2·V2, or if the concentration unit is Molarity, then it can be written as M1·V1 = M2·V2.

Preparing 3.00 L of 0.500 M CaCl2 from a 10.0 M Stock Solution

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Practice Problem: Calculating Concentrations To what volume should 0.200 L of 15 M NaOH solution be diluted to give a 3 M NaOH solution?

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Clicker 3

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  • What is the concentration of HCl in the final solution when 65 mL of a 9.0 M HCl solution is diluted with pure water to a total volume of .15 L?
    • A) 2.1 × 10-2 M
    • B) 3.9 M
    • C) 21 M
    • D) 3.9 × 10^3 M

Vocab

Term Definition
solution homogeneous mixtures
solute component of solution which changes state
dilute solutions solutions which have a small amount of solute compared to solvent
molarity amount of solute (in moles) divided by the volume of solution (in liters)